θ=nπ+(−1)nα,n∈Z; no solution when ∣sinθ∣ would exceed 1
Locked
General solutions of cos θ and tan θcosθ=cosα:θ=2nπ±α;tanθ=tanα:θ=nπ+αLocked
Equations in sin²θ, cos²θ, tan²θsin2θ=sin2α (likewise cos2,tan2) gives θ=nπ±α; both signs of the root countLocked
Equations that reduce to the standard formsFactorise, use identities or divide out a common ratio to reach sinθ=k,cosθ=k or tanθ=k; don't divide by a factor that can be 0Locked